(X-3)/(x^2+5x+4)=0

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Solution for (X-3)/(x^2+5x+4)=0 equation: 


D( x )

x^2+5*x+4 = 0

x^2+5*x+4 = 0

x^2+5*x+4 = 0

x^2+5*x+4 = 0

DELTA = 5^2-(1*4*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)-5)/(1*2) or x = (-9^(1/2)-5)/(1*2)

x = -1 or x = -4

x in (-oo:-4) U (-4:-1) U (-1:+oo)

(X-3)/(x^2+5*x+4) = 0

x^2+5*x+4 = 0

x^2+5*x+4 = 0

DELTA = 5^2-(1*4*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)-5)/(1*2) or x = (-9^(1/2)-5)/(1*2)

x = -1 or x = -4

(x+4)*(x+1) = 0

(X-3)/((x+4)*(x+1)) = 0

x belongs to the empty set

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